This function takes as input a timestamp and a year and updates the timestamp with the year specified in input.
Syntax:
setdateyear (timestamp, year)
Return data type: dual
Arguments:
| Argument | Description |
|---|---|
| timestamp | The date to evaluate as a timestamp or expression resolving to a timestamp, to convert, for example '2012-10-12'. |
| year | A four-digit year. |
Examples and results:
These examples use the date format DD/MM/YYYY. The date format is specified in the SET DateFormat statement at the top of your load script. Change the format in the examples to suit your requirements.
Example 1:
setdateyear ('29/10/2005', 2013)
Returns '29/10/2013
Example 2:
setdateyear ('29/10/2005 04:26:14', 2013)
Returns '29/10/2013 04:26:14'
To see the time part of the timestamp in a chart, you must set the number formatting to Date and choose a value for Formatting that displays time values.
Example 3:
Add the example script to your document and run it. Then add, at least, the fields listed in the results column to a sheet in your document to see the result.
SetYear:
Load *,
SetDateYear(testdates, 2013) as NewYear
Inline [
testdates
1/11/2012
10/12/2012
1/5/2013
2/1/2013
19/5/2013
15/9/2013
11/12/2013
2/3/2014
14/5/2014
13/6/2014
7/7/2014
4/8/2014
];
The resulting table contains the original dates and a column in which the year has be set to 2013.
| testdates | NewYear |
|---|---|
| 1/11/2012 | 1/11/2013 |
| 10/12/2012 | 10/12/2013 |
| 2/1/2012 | 2/1/2013 |
| 1/5/2013 | 1/5/2013 |
| 19/5/2013 | 19/5/2013 |
| 15/9/2013 | 15/9/2013 |
| 11/12/2013 | 11/12/2013 |
| 2/3/2014 | 2/3/2013 |
| 14/5/2014 | 14/5/2013 |
| 13/6/2014 | 13/6/2013 |
| 7/7/2014 | 7/7/2013 |
| 4/8/2014 | 4/8/2013 |
